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NEW QUESTION: 1

Problem: Loopback address on R1 (2026::111:1) is not able to ping the loopback address on DSW2 (2026::102:1).
Configuration of R3:
!
interface Tunnel34
no ip address
ipv6 address 2026::34:1/122
ipv6 enable
ipv6 ospf 6 area 34
tunnel source Serial0/0/0.34
tunnel destination 10.1.1.10
tunnel mode ipv6
!
Configuration of R4:
interface Tunnel34
no ip address
ipv6 address 2026::34:2/122
ipv6 enable
ipv6 ospf 6 area 34
tunnel source Serial0/0/0
tunnel destination 10.1.1.9
!
The Fault Condition is related to which technology?
A. IPv6 OSPF Routing
B. Ipv4 and Ipv6 Interoperability
C. OSPFv3
D. IPv6 Addressing
E. IPv6 RIP Routing
Answer: B
Explanation:
Explanation/Reference:


NEW QUESTION: 2
A DLP administrator is attempting to add a new Network Discover detection server from the Enforce management console. However, the only available options are Network Monitor and Endpoint servers.
What should the administrator do to make the Network Discover option available?
A. Apply a new software license file from the Enforce console
B. Install a new Network Discover detection server
C. Restart the Vontu Monitor Service
D. Restart the Symantec DLP Controller service
Answer: B

NEW QUESTION: 3
Oracle Web Services Manager uses an agent-based approach to providing Web Services security. Where are these agents deployed?
A. In the Oracle WebLogic Server access gate
B. In the Oracle Service Bus proxy pipeline
C. In any IPv4 of Later network firewall
D. In the Oracle Access Manager web gate
E. In the Oracle WebLogic Server Web Service request Interceptors
Answer: D
Explanation:
Explanation/Reference:
You use the Web Services Manager Control Console to define Oracle Web Services Manager components such as server agents. The server agent acts as an enforcement point for security policies.
Point your browser to the Web Services Manager Control Console and log in using your single sign-on user name and password.
The Web Services Manager Control Console is accessed with a URL of the form:
http://<hostname>:port_number/ccore

NEW QUESTION: 4
After encrypting data using the transit secrets engine, you've received the following output. Which of the following is true based upon the output?
1. Key Value
2. --- -----
3. ciphertext vault:v2:45f9zW6cglbrzCjI0yCyC6DBYtSBSxnMgUn9B5aHcGEit71xefPEmmjMbrk3
A. the original encryption key has been rotated at least once
B. this is the second version of the encrypted data
C. similar to the KV secrets engine, the transit secrets engine was enabled using the transit v2 option
D. the data is stored in Vault using a KV v2 secrets engine
Answer: A
Explanation:
When data is encrypted using Vault, the resulting ciphertext is prepended by the version of the key used to encrypt it. In this case, the version is v2, which means that the encryption key was rotated at least one time. Any data that was encrypted with the original key would have been prepended with vault:v1 To rotate a key, use the command vault write -f transit/keys/<key name>/rotate Reference link:- https://learn.hashicorp.com/vault/encryption-as-a-service/eaas-transit