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NEW QUESTION: 1
Windows 10を実行するいくつかのコンピューターがあります。コンピューターはワークグループにあり、BitLockerドライブ暗号化（BitLocker）が有効になっています。
コンピューターをMicrosoft Azure Active Directory（Azure AD）に参加させます。
コンピューターのBitLocker回復キーをAzure ADから回復できることを確認する必要があります。
最初に何をすべきですか？
A. BitLockerを一時停止します。
B. TMPチップを無効にします。
C. BitLockerを無効にします。
D. BitLockerキープロテクターを追加します。
Answer: D
Explanation:
Explanation
References:
https://docs.microsoft.com/en-us/windows/security/information-protection/bitlocker/prepare-your-organization-f
NEW QUESTION: 2
How do you prevent users from posting transactions into a prior accounting period?
A. Check the Closed field in the relevant accounting period record.
B. Populate the Allow Posting To field on the General Ledger Setup window.
C. Check the Date Locked field in the relevant accounting period record.
D. Populate the Allow Posting From field on the General Ledger Setup window.
Answer: D
NEW QUESTION: 3
Which type of attack is based on the probability of two different messages using the same hash function producing a common message digest?
A. How many people must be in the same room for the chance to be greater than even that at least two people share the same birthday?
B. Explanation:
Attacks Against One-Way Hash Functions: A good hashing algorithm should not produce the same hash value for two different messages. If the algorithm does produce the same value for two distinctly different messages, this is referred to as a collision. If an attacker finds an instance of a collision, he has more information to use when trying to break the cryptographic methods used. A complex way of attacking a one-way hash function is called the birthday attack. Now hold on to your had while we go through this -- it is a bit tricky. In standard statistics, a birthday paradox exists. It goes something like this:
How many people must be in the same room for the chance to be greater than even that another person has the same birthday as you?
C. Statistical attack
D. Birthday attack
E. Differential cryptanalysis
F. Differential linear cryptanalysis
Answer: D
Explanation:
This seems a bit backwards, but the difference is that in the first instance, you are looking for someone with a specific birthday date, which matches yours. In the second instance, you are looking for any two people who share the same birthday. There is a higher probability of finding two people who share a birthday than you finding another person sharing your birthday -- thus, the birthday paradox.
This means that if an attacker has one hash value and wants to find a message that hashes to the same hash value, this process could take him years. However, if he just wants to find any two messages with the same hashing value, it could take him only a couple hours. .....The main point of this paradox and this section is to show how important longer hashing values truly are. A hashing algorithm that has a larger bit output is stronger and less vulnerable to brute force attacks like a birthday attack.
Pg 554-555 Shon Harris: All-In-One Certification Exam Guide
Topic 8, Telecommunications, Network, and Internet Security