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NEW QUESTION: 1
Which option describes how a network administrator prevents possible routing for VLSM subnets that are missing
from the routing table?
A. Create a loopback interface with the correct subnet, and then redistribute the connected interface to the routing
table.
B. Create a route for the subnet to the null interface, and then redistribute the static route into the routing process.
C. Create a route for the subnet to the null interface, and the routing protocol automatically injects it into its routing
process.
D. Create a loopback interface with the correct subnet, and the routing protocol automatically injects it into its routing
process.
Answer: B
NEW QUESTION: 2
The difference between a Service Level Agreement (SLA) and an Operional Level Agreement (OLA) is that:
A. An SLA is legally binding, an OLA is a best efforts agreement
B. An SLA is with an external customer, an OLA is with an internal customer
C. An SLA defines the service to be provided, an OLA defines internal support needed to deliver the service
D. An SLA defines Service Level Requirements, an OLA defines Service Level Targets
Answer: A
NEW QUESTION: 3
You create a table with the PERIOD FOR clause to enable the use of the Temporal Validity feature of Oracle Database 12c.
Examine the table definition:
Which three statements are true concerning the use of the Valid Time Temporal feature for the EMPLOYEES table? (Choose three.)
A. Setting the session valid time using DBMS_FLASHBACK_ARCHIVE.ENABLE_AT_VALID_TIME sets the visibility for data manipulation language (DML), data definition language (DDL), and queries performed by the session.
B. The same statement may filter on both transaction time and valid temporal time by using the AS OF TIMESTAMP and PERIOD FOR clauses.
C. The valid time columns are visible by default when the table is described.
D. The valid time columns are not populated by the Oracle Server automatically.
E. The valid time columns employee_time_start and employee_time_end are automatically created.
Answer: B,D,E
NEW QUESTION: 4
A. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
E. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
G. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
H. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: C