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NEW QUESTION: 1
Dockerファイルの説明をドラッグして、右側の正しい説明にドロップします。すべてのオプションが使用されるわけではありません。
Answer:
Explanation:
Explanation
1 - E, 2 - B, 3 - D, 4 - A
NEW QUESTION: 2
あなたはモバイルアプリケーションを設計する会社で働いています。彼らは、プレイヤーの記録が異なるゲームに割り当てられるサーバーを維持しています。追跡システムは新しく、開発中です。
アプリケーションはEntity Frameworkを使用してAzureデータベースに接続します。データベースには、PlayerテーブルとGameテーブルが保持されます。
プレーヤーを追加する場合、コードは新しいプレーヤーレコードを挿入し、既存のゲームレコードと新しいプレーヤーレコードとの関係を追加する必要があります。
アプリケーションは、正しいgameIdとplayerIdを使用してCreatePlayerWithGameを呼び出し、プロセスを開始します。
（行番号は参照用にのみ含まれています。）
次の各ステートメントについて、ステートメントがtrueの場合は[はい]を選択します。それ以外の場合は、[いいえ]を選択します。
注：それぞれの正しい選択は1ポイントの価値があります。
Answer:
Explanation:
Explanation
Many-to-many relationships without an entity class to represent the join table are not yet supported. However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Post)
WithMany(p => p.PostTags)
HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Tag)
WithMany(t => t.PostTags)
HasForeignKey(pt => pt.TagId);
}
}
NEW QUESTION: 3
You create a Web site that is for members only. The Web site allows members to create lists of users that
have access to information about member profiles.
The name of the list is stored in the listName variable. The user name of the user to whom access is given
is stored in the username variable.
You need to enable members to manage their lists of users.
Which code segment should you use?
A. Roles.CreateRole(listName); User.IsInRole(listName);
B. Roles.CreateRole(listName); Roles.AddUserToRole(userName, listName);
C. Roles.RoleExists(listName); User.IsInRole(listName);
D. Roles.RoleExists(listName); Roles.AddUserToRole(userName, listName);
Answer: B