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NEW QUESTION: 1
A. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
B. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
C. CustNo = L.CustNo
D. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo
E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
F. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
H. CustNo
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
J. CustNo IS NULL
K. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: E
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx
NEW QUESTION: 2
What pdadmin server task option is used to add an additional backend server to a WebSEAL junction?
A. -add option.
B. add option.
C. add_server option
D. -a option.
Answer: B
NEW QUESTION: 3
The sexually transmitted disease, sometimes referred to as the silent STD, that is more common than gonorrhea and a leading cause of PID is:
A. syphilis.
B. genital herpes.
C. chlamydia.
D. trichomoniasis.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Chlamydia is a sexually transmitted genital infection and is manifested in males primarily as urethritis and in females as mucopurulent cervicitis. Clinical manifestations of urethritis are often difficult to distinguish from gonorrhea and include mucopurulent discharges of scant or moderate quantity, urethral itching, and burning on urination. Possible complications or sequelae of male urethral infections include epididymitis, infertility, and Reiter syndrome. In homosexual men, receptive anorectal intercourse might result in chlamydial proctitis. In women, the clinical manifestations might be similar to those of gonorrhea and frequently present as a mucopurulent endocervical discharge, with edema, erythema, and easily induced endocervical bleeding caused by inflammation of the endocervical columnar epithelium. However, up to
70% of sexually active women with chlamydial infections are asymptomatic. Complications and sequelae include salpingitis with subsequent risk of infertility, ectopic pregnancy, or chronic pelvic pain.
Asymptomatic chronic infections of the endometrium and fallopian tubes might lead to the same outcome.
Physiological Adaptation