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NEW QUESTION: 1
展示を参照してください。
展示を参照してください。 BR-PC1（192.168.100.10）はインターネットに到達できません。 インターネットへのアクセスはHQサイトを通じてルーティングされ、すべてのNAT構成が適用および検証されています。 BR-PC1のユーザーがtracerouteを実行しました。 問題を診断する次のステップはどれですか？
A. HQ-Rtr1のWAN IPアドレスにtracerouteを実行します。
B. HQ-Rtr1とHQ-Firewallが同じVLAN内にあることを確認します。
C. HQ-FirewallのLAN IPアドレスにPingを送信します。
D. BR-Rtr1とHQ-Rtr1の間のMTUを確認します。
Answer: B
NEW QUESTION: 2
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo L.CustNoWHERE D.CustNo IS NULL
C. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
Answer: C
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php
NEW QUESTION: 3
A vision-related pathology that is caused by diabetes is
A. rhabdomyosarcoma.
B. retinal detachment.
C. retinopathy.
D. supplies.
Answer: C