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NEW QUESTION: 1
次のステートメントのどれがAuto Scalingグループに当てはまりますか？
A. Auto Scalingは約15分ごとに新しいログファイルを発行します。
B. Auto Scalingグループは、自動的に拡大縮小するように設定することはできません。
C. Auto Scalingグループは、API呼び出しから30分以内にログファイルを配信します。
D. Auto Scalingグループは複数のリージョンにまたがることはできません。
Answer: D
Explanation:
Auto Scalingグループには、同じリージョン内の1つ以上のアベイラビリティーゾーンからのEC2インスタンスを含めることができます。ただし、Auto Scalingグループは複数のリージョンにまたがることはできません。
参照：
http://docs.aws.amazon.com/AutoScaling/latest/DeveloperGuide/US_AddAvailabilityZone.html
NEW QUESTION: 2
Who are you most likely to hear from if there are questions about an employee's compensation?
A. A concerned co-worker
B. The employee's department head
C. The employee's manager
D. The employee
Answer: C
NEW QUESTION: 3
The developer wants to write a criteria query that will return the number of orders made by customer of each county.
Assume that customer is an entity with a unidirectional one-to-many relationship to the Order entity and that Address is an embeddable class, with an attribute country of type String.
Which one of the queries below correctly achieves this?
A. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Customer> c = cq.from(Customer.class); cq.select (cb.count(c.join
(customer_. Orders)) , c.get(customers(0), c.get(customer_.address) . get (Address_'country)); (c.get(Customer_.address). get(address_.country));
B. CriteriaBuilder cb = ...
CriteriaQuery cq = cb.createQueryO;
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
Join<Address, String> country = c.join(Customer,.address) .join(Address cq.multiselect(cq.count(o), country );
cq.groupBy(c.get(Customer.address) - get (Address_ . country) ) ;
C. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Custower> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.select(cb.count(o));
cq.groupBy(c.qet(Customer__.address) - get(Address_.country)) ;
D. CriteriaBuilder cb> = ...
CriteriaQuery cq = cb.createQuery();
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.multiselect(cb.count(0), c,get(customer_.address.get(address_.country) cq.groupBy (c.get(customer_.address) .get(address_.country))
Answer: D
Explanation:
Explanation/Reference:
Incorrect: Not B, Not C: Use multiselect, not select. Not D: Use one Join, not two.
Use multiselect, count and Group By. multiselect() method is used because we are going to get compound result and not one entity type.
Example:
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Object[]> query = cb.createQuery(Object[].class);
Root<Department> d = query.from(Department.class);
Join<Department,Teacher> teachers = d.join("teachers");
query.multiselect(d.get("name"),cb.count(teachers)).groupBy(d.get("name")); Reference: Criteria group by clause
NEW QUESTION: 4
You create a new user manually within Workforce Analytics (Admin >User Maintenance) and set up the
user-level tree security. What happens if the role the user is assigned to already has tree security set up?
Please choose the correct answer.
Response:
A. The role-level security would override the user-level security
B. The user-level security would override the role-level security
C. You CANNOT update tree security on an individual user
D. The user-level security would union with the role-level security
Answer: B