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NEW QUESTION: 1
Your customer has many eliminating entries to eliminate intercompany balances. The General Ledger does not include a purpose-built Consolidation feature. How would you automate the process of creating eliminating entries, assuming your customer is not using Oracle Hyperion Financial Close Management?
A. There is no way to automate this process if the customer is not using Oracle Hyperion Financial Close Management
B. Create a manual journal that includes the eliminating entries, and then create a copy of the journal batch every period
C. Use the spreadsheet template that is accessed from the "Create Journal in Spreadsheet" task and import the spreadsheet with the eliminating entries every period
D. Use the General Ledger's Calculation Manager to define an allocation definition to eliminate entries that you can generate every period
Answer: D
Explanation:
Section: (none)
NEW QUESTION: 2
The design document is being written for an IBM Tivoli Netcool/OMNIbus installation in a failover architecture, andsoftware components must be mapped to server hosts In the design, the primary ObjectServer will be installed onSERVER_A and the backup ObjectServer will beinstalled on SERVER_B.A bi-directional gateway will be used tosynchronize data between the ObjectServers.How should the bi-directional gateway component be designed?
A. The gateway should be on SERVER_
B. The gateway should be on SERVER_
C. The gateway writer should be on SERVER_A and gateway reader on SERVER_B
D. The gateway reader should be on SERVER_A and gateway writer on SERVER_B
Answer: B
NEW QUESTION: 3
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten folgende Spalten:
Sie müssen die Gesamtzahl der Kunden ermitteln, die entweder Einlagenkonten oder Darlehenskonten haben, jedoch nicht beide Kontotypen.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
D. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
H. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
Answer: H
Explanation:
Erläuterung
SQL Server stellt den vollständigen Outer-Join-Operator FULL OUTER JOIN bereit, der alle Zeilen aus beiden Tabellen enthält, unabhängig davon, ob die andere Tabelle einen übereinstimmenden Wert hat oder nicht.
Betrachten Sie einen Join der Product-Tabelle und der SalesOrderDetail-Tabelle in ihren ProductID-Spalten. Die Ergebnisse zeigen nur die Produkte mit Kundenaufträgen. Der Operator ISO FULL OUTER JOIN gibt an, dass alle Zeilen aus beiden Tabellen in die Ergebnisse einbezogen werden sollen, unabhängig davon, ob die Tabellen übereinstimmende Daten enthalten.
Sie können eine WHERE-Klausel mit einem vollständigen Outer-Join einfügen, um nur die Zeilen zurückzugeben, bei denen keine übereinstimmenden Daten zwischen den Tabellen vorhanden sind. Die folgende Abfrage gibt nur die Produkte zurück, die keine übereinstimmenden Kundenaufträge haben, sowie die Kundenaufträge, die nicht mit einem Produkt übereinstimmen.
USE AdventureWorks2008R2;
GEHEN
- Das Schlüsselwort OUTER nach dem Schlüsselwort FULL ist optional.
SELECT p.Name, sod.SalesOrderID
AB Produktion.Produkt p
VOLLSTÄNDIGE AUSSENVERBINDUNG Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IST NULL
OR sod.ProductID IS NULL
ORDER BY p.Name;
Referenzen: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx