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NEW QUESTION: 1
Cisco IOSのゾーンベースのポリシーファイアウォールでは、ルータインターフェイスのいくつかがゾーンに割り当てられているときに、ルータによってデフォルトで許可されるトラフィックは3種類あります。
(3つ選択してください)
A. どのゾーンにも割り当てられていないインターフェイス間で流れるトラフィック
B. ゾーンメンバインターフェイスとゾーンメンバではないインターフェイス間を流れるトラフィック
C. トラフィックが返されるゾーンメンバーインターフェイスに流れるトラフィック
D. 同じゾーンのメンバであるインターフェイス間で流れるトラフィック
E. ルータインターフェイスとの間で流れるトラフィック(自己ゾーン)
F. ゾーンメンバーインターフェイスと別のゾーンに属する別のインターフェイスとの間で流れるトラフィック
Answer: A,D,E
Explanation:
Explanation
http://www.cisco.com/en/US/products/sw/secursw/ps1018/products_tech_note09186a00808bc994.shtml Rules For Applying Zone-Based Policy Firewall Router network interfaces' membership in zones is subject to several rules that govern interface behavior, as is the traffic moving between zone member interfaces:
A zone must be configured before interfaces can be assigned to the zone.
An interface can be assigned to only one security zone.
All traffic to and from a given interface is implicitly blocked when the interface is assigned to a zone, except traffic to and from other interfaces in the same zone, and traffic to any interface on the router.
Traffic is implicitly allowed to flow by default among interfaces that are members of the same zone. In order to permit traffic to and from a zone member interface, a policy allowing or inspecting traffic must be configured between that zone and any other zone.
The self zone is the only exception to the default deny all policy. All traffic to any router interface is allowed until traffic is explicitly denied.
Traffic cannot flow between a zone member interface and any interface that is not a zone member. Pass, inspect, and drop actions can only be applied between two zones.
Interfaces that have not been assigned to a zone function as classical router ports and might still use classical stateful inspection/CBAC configuration.
If it is required that an interface on the box not be part of the zoning/firewall policy. It might still be necessary to put that interface in a zone and configure a pass all policy (sort of a dummy policy) between that zone and any other zone to which traffic flow is desired.
From the preceding it follows that, if traffic is to flow among all the interfaces in a router, all the interfaces must be part of the zoning model (each interface must be a member of one zone or another).
The only exception to the preceding deny by default approach is the traffic to and from the router, which will be permitted by default. An explicit policy can be configured to restrict such traffic.

NEW QUESTION: 2
注:この質問は、同じシナリオを提示する一連の質問の一部です。 シリーズの各質問には、記載された目標を達成する可能性のある独自のソリューションが含まれています。 一部の質問セットには複数の正しい解決策がある場合もあれば、正しい解決策がない場合もあります。
質問に答えた後、その質問に戻ることはできません。 その結果、これらの質問はレビュー画面に表示されません。
次のタスクを実行するIoTソリューションを作成する必要があります。
*ハザードを特定
*リアルタイムのオンラインダッシュボードを提供
* 1分ごとにエリアの画像を撮影します
*毎分、エリア内の人数をカウントします
ソリューション:イメージをAzure IoTハブに送信するようにIoTデバイスを構成し、Azureイベントハブに結果を送信するAzure Cognitive ServicesへのAzure Functions呼び出しを構成します。 Azure Stream Analyticsを使用して、イベントハブに接続するようにMicrosoft Power BIを構成します。
これは目標を達成していますか?
A. いいえ
B. はい
Answer: A
Explanation:
Instead use Cognitive Services containers on the IoT devices.
References:
https://azure.microsoft.com/es-es/blog/running-cognitive-services-on-iot-edge/
https://docs.microsoft.com/en-us/azure/iot-hub/iot-hub-live-data-visualization-in-power-bi

NEW QUESTION: 3
You have a database that contains the following tables:

You need to write a query that returns a list of all customers who have not placed orders.
Which Transact-SQL statement should you run?
A. SELECT c.custidFROM Sales.Customers c LEFT OUTER Sales.Order oON c.custid = o.custid
B. SELECT c.custidFROM Sales.Customers c LEFT OUTER JOIN Sales.Order o ON c.custid = o.custidWHERE orderid IS NULL
C. SELECT c.custidFROM Sales.Customers c INNER JOIN Sales.Order oON c.custid = o.custid
D. SELECT custid FROM Sales.CustomersINTERSECTSELECT custid FROM Sales.Orders
Answer: B
Explanation:
Explanation
Inner joins return rows only when there is at least one row from both tables that matches the join condition.
Inner joins eliminate the rows that do not match with a row from the other table. Outer joins, however, return all rows from at least one of the tables or views mentioned in the FROM clause, as long as those rows meet any WHERE or HAVING search conditions. All rows are retrieved from the left table referenced with a left outer join, and all rows from the right table referenced in a right outer join. All rows from both tables are returned in a full outer join.
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

NEW QUESTION: 4
Refer to the exhibit.

What are two effect of this configuration? (Choose two.)
A. The 10.1.1.0/27 subnet is assigned as the inside global address range.
B. Inside source addresses are translated to the 209.165.201.0/27 subnet.
C. It establishes a one-to-one NAT translation.
D. The 209.165.201.0/27 subnet is assigned as the outside local address range.
E. The 10.1.1.0/27 subnet is assigned as the inside local addresses.
Answer: B,E