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NEW QUESTION: 1
공개 된 뉴스 API를 위한 게이트웨이 솔루션을 개발합니다. 뉴스 API 백엔드는 RESTful 서비스로 구현되며 OpenAPI 사양을 사용합니다.
Azure API 관리 서비스 인스턴스를 사용하여 뉴스 API에 액세스 할 수 있는지 확인해야 합니다.
어떤 Azure PowerShell 명령을 실행해야 합니까?
A. New-AzureRmApiManagementBackend -Context $ ApiMgmtContext -Url $ Url -Protocol
http
B. New-AzureRmApiManagement -ResourceGroupName $ ResourceGroup -Name $ 이름 - 위치 $ 위치 - 조직 $ 조직 - 관리자 이메일 $ AdminEmail
C. New-AzureRmApiManagementBackendProxy -Url $ ApiUrl
D. Import-AzureRmApiManagementApi -Context $ ApiMgmtContext -SpecificationFormat
"Swagger"- 지정 경로 $ SwaggerPath - 경로 $ 경로
Answer: C
Explanation:
Explanation
New-AzureRmApiManagementBackendProxy creates a new Backend Proxy Object which can be piped when creating a new Backend entity.
Example: Create a Backend Proxy In-Memory Object
PS C:\>$secpassword = ConvertTo-SecureString "PlainTextPassword" -AsPlainText -Force PS C:\>$proxyCreds = New-Object System.Management.Automation.PSCredential ("foo", $secpassword) PS C:\>$credential = New-AzureRmApiManagementBackendProxy -Url "http://12.168.1.1:8080"
-ProxyCredential $proxyCreds
PS C:\>$apimContext = New-AzureRmApiManagementContext -ResourceGroupName
"Api-Default-WestUS" -ServiceName "contoso"
PS C:\>$backend = New-AzureRmApiManagementBackend -Context $apimContext -BackendId 123 -Url
'https://contoso.com/awesomeapi' -Protocol http -Title "first backend" -SkipCertificateChainValidation $true
-Proxy $credential -Description "backend with proxy server"
Creates a Backend Proxy Object and sets up Backend
NEW QUESTION: 2
R1は、IS-IS、OSPF、RIP、および内部EIGRPを介してルート192.168.12.0/24を学習しました。通常の運用状態では、ルーティングテーブルにインストールされているルーティングプロトコルはどれですか。
A. RIP
B. OSPF
C. IS-IS
D. 内部EIGRP
Answer: D
NEW QUESTION: 3
Allen works as a Software Developer for Mansoft Inc. He creates a Console application. He writes the following line of code in the application:
String str="ABC's World";
According to the given line of code, which of the following are legal statements?
Each correct answer represents a part of the solution. Choose all that apply.
A. str=str+10;
B. int j=str.Length;
C. str=5;
D. str[2]="y";
E. String st1="Hello" + str;
Answer: A,B,E