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NEW QUESTION: 1
The following is the unique "critical" quality risk item that has been identified:
CR-RSK-1. The GUI of the application might accept non-integer values for the input field designed to get the number of bottles from the user
Test analysis for system testing has just begun and the following test conditions have been identified:
TC-SEL-2. Test the selection of the package sizes
TC-SEL-4. Test wrong numbers of bottles for an order
TC-CR-RSK-1. Test the accepted values from the input field designed to get the number of bottles from the user
What is the MINIMUM number of test conditions that must be added to fulfill both the EXCR1 and EXCR2 exit criteria?
Number of correct responses: 1
A. 0
B. 1
C. 2
D. 3
Answer: D
NEW QUESTION: 2
Which two statements about deploying a mesh network by MAPs and RAPs are true on AireOS
8.0?(choose two)
A. The backhaul client access feature cannot be enabled on a RAP that is RAP does not allow clients on its 802.11a radio
B. A MAP/RAP must be authorized by either PSK or EAP before joining a controller in bridge mode.
C. VLAN tags are always forwarded across Mesh links.
D. The three main types of mesh type under the neighbor information are neighbored,parent and child. For types default neighbor and default child default is used when the neighbor BGN is not known of different from the current AP BGNif the strict matching BGN features is disabled.
E. RADIUS and Local authentications are supported with both PSK and EAP.
Answer: D,E
NEW QUESTION: 3
Heniser Pet Foods는 X.와 Y의 두 가지 제품을 생산합니다.
제품 X와 Y는 각각 미화 30 달러와 50 달러입니다. 각 제품은 재료 A와
B. 제품은 6 파운드의 재료 A와 12 파운드의 재료 B를 사용합니다. 제품 Y는 12 파운드의 재료 A와 8 파운드의 재료 B를 사용합니다. 회사는 1,200 파운드의 재료 A와 1,760 파운드의 재료 B 만 구입할 수 있습니다. 제조 할 제품의 최적 혼합은 다음과 같습니다.
A. 40 단위의 X 및 120 단위의 Y.
B. 120 단위 및 40 단위 Y.
C. 0 단위 X 및 100 단위 Y.
D. 146 단위 및 Y 단위 0 단위.
Answer: B
Explanation:
Linear programming is a technique used to maximize a contribution margin function or to minimize a cost function, subject to constraints such as scarce resources or minimum/maximum levels of production. Thus, linear programming is often used for planning resource allocations. In this problem, the equation to be maximized, called the objective function, is: U3 $30)K+ $50Y. This equation is to be maximized subject to the constraints on materials. The two constraint functions are:
Material A: 6X + 12Y < 1,200 Material B: I 2X + 8Y < 1,760
One way to solve this problem is to graph the constraint lines and determine the feasible area. The optimal production level is at an extreme point within the feasible area. The graph shows that a production level of 120 units of and 40 units of Y is a feasible production level that maximizes the contribution margin.
NEW QUESTION: 4
A. Option A
B. Option B
C. Option C
D. Option D
Answer: A