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NEW QUESTION: 1
You are developing a method that uses the Computer Vision client library. The method will perform optical character recognition (OCR) in images. The method has the following code.
During testing, you discover that the call to the GetReadResultAsync method occurs before the read operation is complete.
You need to prevent the GetReadResultAsync method from proceeding until the read operation is complete.
Which two actions should you perform? Each correct answer presents part of the solution. (Choose two.) NOTE: Each correct selection is worth one point.
A. Add code to verify the results.Status value.
B. Add code to verify the status of the txtHeaders.Status value.
C. Wrap the call to GetReadResultAsync within a loop that contains a delay.
D. Remove the Guid.Parse(operationId) parameter.
Answer: A,C
Explanation:
Example code :
do
{
results = await client.GetReadResultAsync(Guid.Parse(operationId));
}
while ((results.Status == OperationStatusCodes.Running ||
results.Status == OperationStatusCodes.NotStarted));
Reference:
https://github.com/Azure-Samples/cognitive-services-quickstart-code/blob/master/dotnet/ComputerVision/ComputerVisionQuickstart.cs
NEW QUESTION: 2
Your company has a testing environment that contains an Active Directory domain named contoso com The domain contains a server named Server1 that runs Windows Server 2016. Server1 has IP Address Management (IPAM) installed IPAM has the following configuration.
The IPAM Overview page from Server Manager is shown in the IPAM Overview exhibit.
For each of the following statements, select Yes if the statement is true Otherwise, select No
Answer:
Explanation:
Explanation
NEW QUESTION: 3
An engineer is designing an IP addressing scheme for a local company that requires multicast for its
application. For security reasons, only explicitly configured devices can be permitted to transmit across the
network.
Which multicast technology and address range must the engineer select?
A. ASM; 232.0.0.0/8
B. SSM; 232.0.0.0/8
C. SSM; 224.0.0.0/8
D. PIM-SM; 232.0.0.0/8
Answer: B