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NEW QUESTION: 1
Which three of these are considered Cisco Unified Communications Manager Network services?
A. Cisco DirSync
B. Cisco CallManager
C. Cisco DB Replicator
D. Cisco TFTP
E. Cisco CallManager Admin services
F. Cisco CDP
Answer: C,E,F
Explanation:
Reference : Cisco Unified Serviceability Administration Guide , Release 8.6(1), page-91
A. The Cisco CallManager service provides software-only call processing as well as signaling and
call control functionality for Cisco Unified Communications Manager.
This is part of the feature services.
E. TFTP is part of the CM Services
F. DirSync is a directory service
NEW QUESTION: 2
To which layer of the OSI model would the ACI concepts of BD (SVI) and private network (VRF lite) map?
A. session
B. transport
C. data link
D. network
E. presentation
F. Physic
G. application
Answer: D
NEW QUESTION: 3
Tracing has been enabled for the HR user. You execute the following command to check the contents of the orcl_25052.trc trace file, which was generated during tracing:
Which two statements are correct about the execution of the command?
A. TKPROF use TEMP_PLAN_TABLE in the HR schema as a temporary plan table.
B. SCRIPT.SQL stores the statistics for all traced SWL statements.
C. SQL statements in the output files are stored in the order of elapsed time.
D. Execution plans for SQL statements are stored in TEMP_PLAN_TABLE and can be queried by the user.
E. Recursive SQL statements are included in the output file.
Answer: A,B
Explanation:
INSERT Creates a SQL script that stores the trace file statistics in the database. TKPROF creates this script with the name filename3. This script creates a table and inserts a row of statistics for each traced SQL statement into the table.
NEW QUESTION: 4
You need an algorithm that must:
Print the characters of a String, in index order
Skip all instances of the character 'a' that appear in the String
Given:
2. public void foo (String s) {
3. // insert code here
4. }
Which two, inserted independently at line 3, correctly implement the algorithm? (Choose two.)
A. int i = 0;
while (i < s.length()) {
if (s.charAt(i) != 'a') {
System.out.print(i);
}
i++;
}
B. for (int i = 0; i < s.length(); i++) {
if (s.charAt(i) != 'a') System.out.print(i);
}
C. for(char c:s) {
if (c != 'a') System.out.print(c);
}
D. int i = 0;
while (i < s.length()) {
if (s.charAt(i) != 'a') {
System.out.print(s.charAt(i));
}
i++;
}
E. for(int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
if (c != 'a') System.out.print(c);
}
Answer: D,E