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NEW QUESTION: 1
2つの類似したストーリーAとBが3ストーリーポイントで推定されます。ストーリーCが推定されますa（8ポイントAとCが完了した反復を変更すると、ストーリーAがストーリーCよりもはるかに長くかかったことがわかります。
アジャイル開業医は何をすべきですか？
A. より良い見積もりを提供するために、ストーリーBに8ストーリーポイント以上を割り当てます
B. ストーリーBにより多くのリソースを割り当てて、見積もりと一致させる
C. A BおよびCの値を含むすべてのストーリーを再推定します
D. エラーを考慮してストーリーBの反復にポイントを追加しますが、ストーリーBは3ポイントに保ちます
Answer: C
NEW QUESTION: 2
You have the following X++ code: (Line numbers are included for reference only.)
Methodl and method2 are in Classl. Method3 is in Class2. You need to set variablel for classlObj to a value of 5. Which code segment should you insert at line 21?
A. classl0bj.methodl(5);
B. classlObj.variable1= 5;
C. this.variablel =5;
D. new Classl().methodl(5);
Answer: D
NEW QUESTION: 3
To allow or prevent load balancing to network 172.16.3.0/24, which of the following commands could be used in R2? (Choose two.)
A. R2(config-if)#clock rate
B. R2(config-if)#bandwidth
C. R2(config-if)#ip ospf cost
D. R2(config-router)#distance ospf
E. R2(config-if)#ip ospf priority
Answer: B,C
Explanation:
OSPF Cost
http://www.cisco.com/en/US/tech/tk365/technologies_white_paper09186a0080094e9e.shtml#t6
The cost (also called metric) of an interface in OSPF is an indication of the overhead required to send packets across a certain interface. The cost of an interface is inversely proportional to the bandwidth of that interface. A higher bandwidth indicates a lower cost.
There is more overhead (higher cost) and time delays involved in crossing a 56k serial line than crossing a 10M ethernet line. The formula used to calculate the cost is:
cost= 10000 0000/bandwith in bps
For example, it will cost 10 EXP8/10 EXP7 = 10 to cross a 10M Ethernet line and will cost 10 EXP8/1544000 =64 to cross a T1 line.
By default, the cost of an interface is calculated based on the bandwidth; you can force the cost of an interface with the ip ospf cost <value> interface subconfiguration mode command.