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NEW QUESTION: 1
会社には、オンプレミスデータセンターのMySQLサーバーに接続するDockerコンテナーで実行されているWebアプリケーションがあります。このアプリケーションの展開と保守は時間がかかり、新機能のリリースが遅くなっています。同社は、アプリケーションをAWSに移行し、インフラストラクチャの管理と展開を促進するサービスを使用したいと考えています。
会社はAWSでどのアーキテクチャを検討すべきですか？ （2つ選択してください。）
A. AWS Elastic Beanstalk Docker Single Container for the web application, and an Amazon RDS for MySQL for the database.
B. AWS CloudFormation with Lambda Custom Resources without VPC for the web application, and an Amazon RDS for MySQL database.
C. AWS Elastic Beanstalk Docker Multi-container either for the web application or database.
D. Amazon ECS for the web application, and an Amazon RDS for MySQL for the database.
E. AWS CloudFormation with Lambda Custom Resources running in a VPC for the web application, and an Amazon RDS for MySQL database.
Answer: A,E
Explanation:
Explanation
Both helps facilitate infrastructure management and deployment. Check out this article on "Why Use AWS Lambda in a Custom VPC?": https://aws.amazon.com/blogs/apn/why-use-aws-lambda-in-a-custom-vpc/
NEW QUESTION: 2
You are working for a company that designs mobile applications. They maintain a server where player records are assigned to their different games. The tracking system is new and in development.
The application uses Entity Framework to connect to an Azure Database. The database holds a Player table and Game table.
When adding a player, the code should insert a new player record, and add a relationship between an existing game record and the new player record.
The application will call CreatePlayerWithGame with the correct gameIdand the playerId to start the process.
(Line numbers are included for reference only.)
For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Explanation
Many-to-many relationships without an entity class to represent the join table are not yet supported.
However, you can represent a many-to-many relationship by including an entity class for the join table and mapping two separate one-to-many relationships.
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.Entity<PostTag>()
HasKey(t => new { t.PostId, t.TagId });
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Post)
WithMany(p => p.PostTags)
HasForeignKey(pt => pt.PostId);
modelBuilder.Entity<PostTag>()
HasOne(pt => pt.Tag)
WithMany(t => t.PostTags)
HasForeignKey(pt => pt.TagId);
}
}
NEW QUESTION: 3
View the Exhibit.
Assume the product attribute does NOT yet exist in any scope.
Which two create an instance of com.example.Product and initialize the name and price properties to the name and price request parameters? (Choose two)
A. <jsp:useBean id="product" class="com.example.Product" />
< jsp:setProperty name="product" property="name"
value="${param.name}" />
< jsp:setProperty name="product" property="price"
value="${param.price}" />
B. <jsp:useBean id="product" class="com.example.Product">
< jsp:setProperty name="product" property="name"
value="${name}" />
< jsp:setProperty name="product" property="price"
value="${price}" />
< /jsp:useBean>
C. <jsp:useBean id="product" class="com.example.Product" />
< % product.setName( request.getParameter( "name" ) ); %>
< % product.setPrice( request.getParameter( "price" ) ); %>
D. <jsp:useBean id="product" class="com.example.Product" />
< jsp:setProperty name="product" property="*" />
Answer: A,D