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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same scenario. For you convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question in this series.
Start of repeated scenario.
You work for a company named Contoso, Ltd.
The network contains an Active Directory forest named contoso.com. A forest trust exists between contoso.com and an Active Directory forest named adatum.com.
The contoso.com forest contains the objects configured as shown in the following table.
Group1 and Group2 contain only user accounts.
Contoso hires a new remote user named User3. User3 will work from home and will use a computer named Computer3 that runs Windows 10. Computer3 is currently in a workgroup.
An administrator named Admin1 is a member of the Domain Admins group in the contoso.com domain.
From Active Directory Users and Computers, you create an organizational unit (OU) named OU1 in the contoso.com domain, and then you create a contact named Contact1 in OU1.
An administrator of the adatum.com domain runs the Set-ADUser cmdlet to configure a user named User1 to have a user logon name of [email protected].
End or repeated scenario.
You need to join Computer3 to the contoso.com domain by using offline domain join.
Which command should you use in the contoso.com domain and on Computer3? To answer, select the appropriate options in the answer area.
Answer:
Explanation:
Explanation
NEW QUESTION: 2
What uses a key of the same length as the message where each bit or character from the plaintext is encrypted by a modular addition?
A. Running key cipher
B. Steganography
C. Cipher block chaining
D. One-time pad
Answer: D
Explanation:
Explanation/Reference:
Explanation:
In cryptography, the one-time pad (OTP) is an encryption technique that cannot be cracked if used correctly. In this technique, a plaintext is paired with a random secret key (also referred to as a one-time pad). Then, each bit or character of the plaintext is encrypted by combining it with the corresponding bit or character from the pad using modular addition. If the key is truly random, is at least as long as the plaintext, is never reused in whole or in part, and is kept completely secret, then the resulting ciphertext will be impossible to decrypt or break. However, practical problems have prevented one-time pads from being widely used.
The "pad" part of the name comes from early implementations where the key material was distributed as a pad of paper, so that the top sheet could be easily torn off and destroyed after use.
The one-time pad has serious drawbacks in practice because it requires:
Truly random (as opposed to pseudorandom) one-time pad values, which is a non-trivial requirement.
Secure generation and exchange of the one-time pad values, which must be at least as long as the
message. (The security of the one-time pad is only as secure as the security of the one-time pad exchange).
Careful treatment to make sure that it continues to remain secret, and is disposed of correctly
preventing any reuse in whole or part-hence "one time".
Because the pad, like all shared secrets, must be passed and kept secure, and the pad has to be at least as long as the message, there is often no point in using one-time padding, as one can simply send the plain text instead of the pad (as both can be the same size and have to be sent securely).
Distributing very long one-time pad keys is inconvenient and usually poses a significant security risk. The pad is essentially the encryption key, but unlike keys for modern ciphers, it must be extremely long and is much too difficult for humans to remember. Storage media such as thumb drives, DVD-Rs or personal digital audio players can be used to carry a very large one-time-pad from place to place in a non- suspicious way, but even so the need to transport the pad physically is a burden compared to the key negotiation protocols of a modern public-key cryptosystem, and such media cannot reliably be erased securely by any means short of physical destruction (e.g., incineration).
The key material must be securely disposed of after use, to ensure the key material is never reused and to protect the messages sent. Because the key material must be transported from one endpoint to another, and persist until the message is sent or received, it can be more vulnerable to forensic recovery than the transient plaintext it protects.
Incorrect Answers:
A: Running key cipher does not use a key of the same length as the message.
C: Steganography is a method of hiding data in another media type so the very existence of the data is concealed. This is not what is described in the question.
D: Cipher block chaining is an encryption method where each block of text, the key, and the value based on the previous block are processed in the algorithm and applied to the next block of text. This is not what is described in the question.
References:
https://en.wikipedia.org/wiki/One-time_pad
NEW QUESTION: 3
システム管理者はどのようにしてアカウント名が一意であることを確認できますか？
A. アカウント名の検証ルールでVLOOKUP演算子を使用します
B. APEXトリガーを使用
C. アカウント名の検証ルールでHLOOKUP演算子を使用します
D. アカウント名フィールドを一意にします
Answer: B