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NEW QUESTION: 1
シスコのベストプラクティスによると、どの3つのプロトコルは、デフォルトACLがネットワークへの有効な資格情報を提供し、接続するための有線BYODデバイスを有効にするには、アクセスポート上で許可する必要がありますか？ （3を選択してください。）
A. TFTP
B. DNS
C. BOOTP
D. MAB
E. 802.1x
F. HTTP
Answer: A,B,C
Explanation:
ACLs are the primary method through which policy enforcement is done at access layer switches for wired devices within the campus.
ACL-DEFAULT--This ACL is configured on the access layer switch and used as a default ACL on the port. Its purpose is to prevent un-authorized access.
An example of a default ACL on a campus access layer switch is shown below:
Extended IP access list ACL-DEFAULT
10 permit udp any eq bootpc any eq bootps log (2604 matches) 20 permit udp any host 10.230.1.45 eq domain
30 permit icmp any any
40 permit udp any any eq tftp
50 deny ip any any log (40 matches)
As seen from the output above, ACL-DEFAULT allows DHCP, DNS, ICMP, and TFTP traffic and denies everything else.
Source: http://www.cisco.com/c/en/us/td/docs/solutions/Enterprise/Borderless_Networks/Unified_Access/ BYOD_Design_Guide/BYOD_Wired.html MAB is an access control technique that Cisco provides and it is called MAC Authentication Bypass.
NEW QUESTION: 2
Examine the business rule:
Each student can work on multiple projects and each project can have multiple students.
You need to design an Entity Relationship Model (ERD) for optimal data storage and allow for generating reports in this format:
STUDENT_ID FIRST_NAME LAST_NAME PROJECT_ID PROJECT_NAME PROJECT_TASK
Which two statements are true in this scenario?
A. PROJECT_IDmust be the primary key in the PROJECTSentity and foreign key in the STUDENTSentity.
B. The ERD must have a M:M relationship between the STUDENTSand PROJECTSentities that must be resolved into 1:M relationships.
C. An associative table must be created with a composite key of STUDENT_ID and PROJECT_ID, which is the foreign key linked to the STUDENTS and PROJECTS entities.
D. The ERD must have a 1:M relationship between the STUDENTSand PROJECTSentities.
E. STUDENT_IDmust be the primary key in the STUDENTSentity and foreign key in the PROJECTSentity.
Answer: B,C
Explanation:
Explanation/Reference:
References:
http://www.oracle.com/technetwork/issue-archive/2011/11-nov/o61sql-512018.html
NEW QUESTION: 3
Two routers named Atlanta and Brevard are connected by their serial interfaces as shown in the exhibit, but there is no data connectivity between them. The Atlanta router is known to have a correct configuration. Given the partial configurations shown in the exhibit, what is the problem on the Brevard router that is causing the lack of connectivity?
A. insufficient bandwidth
B. incorrect subnet mask
C. IPCP closed
D. Link reliability too low
E. incompatible encapsulation
F. incompatible IP addresses
Answer: F
Explanation:
Answer A is correct because Interface Serial 0 of Atlanta Router has 192.168.10.1 And Interface Serial 1 of Router Brevard has 192.168.11.2. These are from different network.