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NEW QUESTION: 1
A comprehensive IS audit policy should include guidelines detailing what involvement the internal audit team should have?
A. in the acquisition and maintenance of major WEB applications.
B. in the human resource management cycle of the application development project.
C. in the development and coding of major OS applications.
D. None of the choices.
E. in the development, acquisition, conversion, and testing of major applications.
Answer: E
Explanation:
Explanation/Reference:
Explanation:
The audit policy should include guidelines detailing what involvement internal audit will have in the development, acquisition, conversion, and testing of major applications. Such a policy must be approved by top management for it to be effective.

NEW QUESTION: 2
Identify three true statements regarding Multiple Organization reporting. (Choose three.)
A. Cross Organization reports and multiple Organization reports are the same.
B. Multiple Organization reports can be submitted for a Reporting Level of Ledger.
C. Cross Organization reports produce outputs across different Operating Units in a single report from a single responsibility.
D. Multiple Organization reports produce outputs for different Operating Units one at a time from a single responsibility.
E. Multiple Organization reports produce outputs for different Operating Units in a single report output from a single responsibility.
F. Cross Organization reports can be submitted for a reporting Level of Ledger.
Answer: B,C,D

NEW QUESTION: 3
展示を参照してください。

Link1は銅線接続で、Link2はファイバー接続です。ファイバポートは、すべての転送のプライマリポートである必要があります。 SW2でのshow spanning-treeコマンドの出力は、ファイバーポートがスパニングツリーによってブロックされていることを示しています。エンジニアがSW2のGO / 1でspanning-tree port-priority 32コマンドを入力しましたが、ポートはブロックされたままです。問題を解決するには、Link2に接続されているポートでどのコマンドを入力する必要がありますか?
A. SW1にスパニングツリーポートプライオリティ224を入力します。
B. SW2でスパニングツリーポートプライオリティ64を入力します。
C. SW2のスパニングツリーポートプライオリティ4を入力します。
D. SW1にスパニングツリーポートプライオリティ32を入力します。
Answer: D
Explanation:
Explanation
SW1 needs to block one of its ports to SW2 to avoid a bridging loop between the two switches.
Unfortunately, it blocked the fiber port Link2. But how does SW2 select its blocked port? Well, the answer is based on the BPDUs it receives from SW1. answer 'Enter spanning-tree port-priority 32 on SW1' BPDU is superior than another if it has:
1. answer 'Enter spanning-tree port-priority 32 on SW1' lower Root Bridge ID
2. answer 'Enter spanning-tree port-priority 32 on SW1' lower path cost to the Root
3. answer 'Enter spanning-tree port-priority 32 on SW1' lower Sending Bridge ID
4. answer 'Enter spanning-tree port-priority 32 on SW1' lower Sending Port ID These four parameters are examined in order. In this specific case, all the BPDUs sent by SW1 have the same Root Bridge ID, the same path cost to the Root and the same Sending Bridge ID.
The only parameter left to select the best one is the Sending Port ID (Port ID = port priority + port index). And the port index of Gi0/0 is lower than the port index of Gi0/1 so Link 1 has been chosen as the primary link.
Therefore we must change the port priority to change the primary link. The lower numerical value of port priority, the higher priority that port has. In other words, we must change the port-priority on Gi0/1 of SW1 (not on Gi0/1 of SW2) to a lower value than that of Gi0/0.