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NEW QUESTION: 1
Which of the following statements relating to the Biba security model is FALSE?
A. It is a state machine model.
B. A subject is not allowed to write up.
C. Programs serve as an intermediate layer between subjects and objects.
D. Integrity levels are assigned to subjects and objects.
Answer: C
Explanation:
The Biba model was developed after the Bell-LaPadula model. It is a state machine model and is very similar to the Bell-LaPadula model but the rules are 100% the opposite of Bell-LaPadula.
Biba addresses the integrity of data within applications. The Bell-LaPadula model uses a lattice of security levels (top secret, secret, sensitive, and so on). These security levels were developed mainly to ensure that sensitive data was only available to authorized individuals. The Biba model
is not concerned with security levels and confidentiality, so it does not base access decisions upon
this type of lattice. The Biba model uses a lattice of integrity levels instead of a lattice of
confidentiality levels like Bel-LaPadula.
If implemented and enforced properly, the Biba model prevents data from any integrity level from
flowing to a higher integrity level. Biba has two main rules to provide this type of protection:
*-integrity axiom A subject cannot write data to an object at a higher integrity level (referred to as
"no write up").
Simple integrity axiom A subject cannot read data from a lower integrity level (referred to as "no
read down").
Extra Information on clark-wilson model to understand the concepts:
The Clark-Wilson model was developed after Biba and takes some different approaches to
protecting the integrity of information. This model uses the following elements:
Users Active agents
Transformation procedures (TPs) Programmed abstract operations, such as read, write, and
modify
Constrained data items (CDIs) Can be manipulated only by TPs
Unconstrained data items (UDIs) Can be manipulated by users via primitive read and write
operations
Integrity verification procedures (IVPs) Run periodically to check the consistency of CDIs with
external reality
The other answers are incorrect:
It is a state machine model: Biba model is a state machine model and addresses the integrity of
data within applications.
A subject is not allowed to write up is a part of integrity axiom in the Biba model.
Integrity levels are assigned to subjects and objects is also a characteristic of Biba model as it
addresses integrity.
Reference(s) used for this question:
Shon Harris , AIO v3 , Chapter-5 : Security Models and Architecture , Page : 282 - 284
Reference: AIOv4 Security Architecture and Design (pages 338 - 342)
AIOv5 Security Architecture and Design (pages 341 - 344)
NEW QUESTION: 2
Mit Microsoft SQL Server 2012 erstellen Sie eine gespeicherte Prozedur, wie im folgenden Codesegment gezeigt.
(Zeilennummern dienen nur als Referenz.)
Die Prozedur kann innerhalb anderer Transaktionen aufgerufen werden.
Sie müssen sicherstellen, dass die Änderung auch dann beibehalten wird, wenn die DELETE-Anweisung aus der HumanResourcesJobCandidate-Tabelle erfolgreich ausgeführt wurde, selbst wenn das Einfügen in die Audit.Log-Tabelle fehlschlägt.
Welches Codesegment sollten Sie in Zeile 14 einfügen?
A. IF (XACT_STATE ()) = 1
B. IF @@ TRANCOUNT = l
C. IF @@ TRANCOUNT = 0
D. IF (XACT_STATE ()) = 0
Answer: A
Explanation:
Reference:
http://msdn.microsoft.com/en-us/library/ms189797.aspx
http://msdn.microsoft.com/en-us/library/ms187967.aspx
NEW QUESTION: 3
Which parameter or parameters are used to calculate OSPF cost in Cisco routers?
A. Bandwidth and Delay
B. Bandwidth, MTU, Reliability, Delay, and Load
C. Bandwidth, Delay, and MTU
D. Bandwidth
Answer: D
Explanation:
http://www.cisco.com/en/US/tech/tk365/technologies_white_paper09186a0080094e9e.shtml#t6
OSPF Cost
The cost (also called metric) of an interface in OSPF is an indication of the overhead required to send packets across a
certain interface. The cost of an interface is inversely proportional to the bandwidth of that interface. A higher
bandwidth indicates a lower cost. There is more overhead (higher cost) and time delays involved in crossing a 56k
serial line than crossing a 10M Ethernet line. The formula used to calculate the cost is:
Cost= 10000 0000/bandwidth in bps
For example, it will cost 10 EXP8/10 EXP7 = 10 to cross a 10M Ethernet line and will cost 10 EXP8/1544000 =64 to
cross a T1 line. By default, the cost of an interface is calculated based on the bandwidth; you can force the cost of an
interface with the ip ospf cost <value> interface sub configuration mode command.