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NEW QUESTION: 1
CAT5eケーブルのテストが必要です。テスト結果の概要は画面に表示されます。
ステップ1：ケーブルテスト結果の作成に使用したツールを選択します。
ステップ2：テスト結果を解釈し、結果を説明するオプションを選択します。分析が完了したら、[ケーブルテスト分析の送信]ボタンをクリックします。
Answer:
Explanation:
Explanation:
A Cable Certifier provides "Pass" or "Fail" information in accordance with industry standards but can also show detailed information when a "Fail" occurs. This includes shorts, the wire pairs involved and the distance to the short. When a short is identified, at the full length of the cable it means the cable has not been crimped correctly.
NEW QUESTION: 2
A. Option D
B. Option A
C. Option B
D. Option C
Answer: A,D
NEW QUESTION: 3
You administer a Microsoft SQL Server 2008 R2 database that contains an OrderItems table. The table has the following definition:
The following DDL has been run on the database:
CREATE PARTITION FUNCTION FUNC_FG (INT)
AS RANGE LEFT FOR VALUES (1, 100, 1000);
You need to create a partition scheme that will place all data to the SECONDARY filegroup.
What should you do?
A. Create a new Filegroup.
Create a new database File.
Use the ALTER PARTITION SCHEME statement along with the NEXT USED clause.
Use the ALTER PARTITION FUNCTION statement along with the SPLIT RANGE clause.
B. Use the ALTER PARTITION FUNCTION ... SPLIT RANGE statement.
C. Execute the DBCC CLEANTABLEcommand on the OrderItems table.
D. Run the following statement:
EXECUTE sp_tableoption
@TableNamePattern ='OrderItem3',
@OptionName= 'PartltionByYear';
@OptionValue= 'true';
E. Create a new filegroup.
Create a new database file.
Use the ALTER PARTITION SCHEME statement along with the NEXT USED clause.
Use ALTER INDEX REORGANIZE statement.
F. Run the following statement:
CREATE PARTITION SCHEME SEC_FG
AS PARTITION FUNC_FG
ALL TO (SECONDARY);
G. Create a new table.
Use the ALTER TABLE statement along with the SWITCH PARTITION clause.
Use the ALTER PARTITION FUNCTION statement along with the MERGE RANGE
clause.
H. Remove the clustered index from the table.
I. Use the ALTER TABLEstatement to remove the COLLATEoption.
J. Create a new partition function.
Create a new partition scheme.
Add a clustered index to place the data onto the partition scheme.
Answer: F